In a rectangle, the length is three more than one half of the width. If the area is 56, what is the width?

Question

In a rectangle, the length is three more than one half of the width. If the area is 56, what is the width?

Answer 1

L = W/2 + 3

LW = 56

(W/2 + 3)W = 56

(W^2)/2 +3W - 56 = 0

W = 8 and -14(reject)

Answer 2

a = l x w

56 = (3 + 1/2w)w

Now you have to distribute the w

And this is the point where I draw a blank...I'm guessing

56 = 3w + 1/2 w (2nd power)

Then solve for w