Question:

In an ac circuit, a 0.025 H inductor is connected to a generator that has an rms voltage of 25 V and operates

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at 50.0 Hz. what is the rms current throgh the inducator

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  1. The inductive reactance (X) is found by the formula:

    X = 2πfL, where f is the frequency and L is the inductance in henries.

    Thus the reactance X equals 6.283 * 50 * 0.025 = 7.854 reactive ohms

    The rms current is found by dividing the rms voltage by the reactance

    so it equals 25/7.854 or 3.183 amperes.

    (This answer assumes a pure inductive circuit.)


  2. Irms = Vrms / XL = Vrms / ωL = Vrms / 2πfL

    = 25.0 V / (2π x 50.0 Hz x 0.025 H)

    = 25.0 V / (314 rad/s x 0.025 H)

    = 25.0 V / 7.85 Ω

    = 3.18 A

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