In an addition problem 24 different integers that can be formed by using each of t?

Question

In an addition problem 24 different integers that can be formed by using each of the digits 1,2,3 and 4 exactly once in each integer, are listed. What is the sum of these 24 integers?

Answer 1

I think you can just do it by inspection.  Maybe I miss the point.

If you have each number in each place, then I guess the sum is easy.

For 24 number each digit appears in each place 6 times.

[If you like for a 1 in the first place there are 3*2*1 = 6 ways to order teh other digits, so 1 appears first 6 times.]

In the 1000s digit you must have each digit 6 times.

In each position, WXYZ, each number appears 6 times so something like;

1*6 + 2*6 + 3*6 + 4*6

(1+2+3+4)*6 = 10 * 6 = 60

So the sum must be something like;

1000*60 + 100*60 + 10*60 + 60 = (1111)*60 = 66660

Answer 2

the no.s r

1234

1243

1324

1342

1423

1432

2134

2143

2341

2314

2431

2413

3214

3241

3124

3142

3421

3412

4123

4132

4213

4231

4312

4321



add them up ,by using the calculator.

:))))

Answer 3

Dont ask such questions and waste your points. They are very precious.