Question:

In how many ways can you choose 5 items from 12 items if the order in which you choose them is important?

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Mathematics

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  1. I think you use nPr

    I only know how to do it if you have a graphing calculator but im pretty sure you just do

    12P5 or 12 nPr 5

    if you have a graphing calculator just put it in like that

    If it tells you the different things you need to tell us that too, because then you have to use factorials (i think thats what they are called they look like this "!")


  2. This is the number of combinations of 5 out of 12, expressed

    12C5

    = 12! / [(5!)*(7!)]

    Cancelling out 7! in Numerator and denominator leaves

    !2*11*10*9*8 / 5*4*3*2*1

    cnacelling out '12' above with '4*3' below, '10' above with '5*2' below

    11*9*8= 752

    is the answer

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