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In stoichiometry reaction,what the result if 10ml of 0.1M NaOH are change with 10ml of 6M NaOH?

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In stoichiometry reaction,what the result if 10ml of 0.1M NaOH are change with 10ml of 6M NaOH?

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  1. Moles NaOH = 0.010 L x 0.1 M= 0.0010

    Moles NaOH = 0.010 L x 6 M =0.060

    total moles = 0.0010 + 0.060 =0.061

    Total volume = 0.020 L

    concentration NaOH = 0.061 / 0.020 = 3.05 M

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