Inserting parenthesis to make the equation true? Please help!?

Question

I've been stuck at this question for an hour now, and I haven't even come close to the solution!

DIRECTIONS:

Read the following equation. Insert ONLY PARENTHESIS in areas where it is needed to make the equation true. You CANNOT change anything else (no changing the what number it is, the order of numbers, switching the signs etc.)

34 * 6^3 ÷ 2^2 * 3^2 - 1 = 170

I tried all different sorts of ways, but the lowest I got was like 229! Can anyone explain to me how you get the answer? Thank you so much!

Answer 1

i am also getting answer round to 229 by placing parenthesis  at

{(34*6^3)/(2^2*(3^2-1))}

Answer 2

34 * ({6^3 ÷ [2^2 * 3^2]} - 1) = 170

Ok, this is how you get the right answer, i dunno about the brackets. for the oder of them do them [ ], then { } then ( ), but do all the powers first.

Do all the intergers first, i didnt but brackets around them because it confuses things.

So now it looks like

34 * 216 ÷ 4 * 9 - 1 = 170,

Now do the 4*9 part

34 * 216 ÷ 36 - 1 = 170

Now do the 216/36 part.

34 * 6 - 1 = 170

Now do the 6-1 part

34 * 5 = 170.

And its true now =)