Integers Help (Easy)?

Question

Stuck on this question: [2 - (-6+3)2]2

The 2 after the bracet is suppose to be those small 2's.

like 32 = 3x3

Answer 1

[2 - (-6+3)2]^2

= [2 - (-3)2]^2

= [2 - (-6)]^2

=[2 + 6]^2

= 8^2

= 64

Answer 2

You mean, like an exponent or "power"? Here is a link to some good acronyms for the "order of operations":

http://math.about.com/library/weekly/aa0...

Knowing the order of operations alone will help you solve this problem.

As for the little 2, is it up to the right of the outside bracket? If so the answer you get after solving everything within the parenthesis and brackets should be multiplies by itself, or in other words, the power of 2.

Answer 3

Is this rewritten correctly?

[2 - (-6 + 3)^2]^2

You need to work from the inside out.

Inner parentheses and brackets are done first, then exponents:

[2 - (-3)^2]^2

[2 - 9]^2

[-7]^2

49

Answer 4

Answer is 64

Answer 5

it is simple

[2-(-6+3)2]2

First sole parentheses

= [2+6]2

= 16 answer

Answer 6

i think what you're talking about is 3 squared.

often it's written as  3^2

if you wanted to indicate square root, it would be  3^0.5  or  3^.5

google calculator uses this convention.  eg

24/2^2/9^.5  when you put this on the google search line, you get:

(24 / (2^2)) / (9^.5) = 2

so, for your problem, it would be

(2-(-6+3)^2)^2

(2 - (((-6) + 3)^2))^2 = 49