Introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant "G"

Question

uses lead spheres of masses 0.64kg and 2.01g whose centers are separated by 6.16cm

Calculation the gravitational force between these spheres, treating each as a point mass located at the center of the sphere. The value of the universal gravitational constant is 6.67259 x 10^-11 N m^2/kg^2. Answer is units of N.

Answer 1

This IS in your book.

F = GMm/r²

where BOTH M&m are in kg, r is in meters, and The units of F are Newtons.

Answer 2

F = (Gm1m2)/d^2

= 6.67259 x 10^-11 N m^2/kg^2(.64kg)(.00201kg))/(.0616m)^2

= 0.0000000000226209 N

= 2.26209 x 10^-11 N

That's it.

It's a straight application of Newton's law of gravitation.

Just make sure on these to keep the units consistent.

bye for now.