Iron and chlorine react to form Iron(III) chloride.at what absoloute temperature would 5.68 L of chlorine

Question

at 2.3 atm need to be to completely react with 4.25g of iron?

if you can explain the procedure I appreciate it

Answer 1

first the equation:

2Fe+3Cl2->2FeCl3

so use dimensional analysis w/ the 4.25 g of iron

4.25g Fe/55.84g*1mol/2mol*3mol=.11416mol of Cl2

and then PV=nRT

solve for T