Is .9999(Repeating)=1 or is it not equal to 1?

Question

Is .9999(Repeating)=1 or is it not equal to 1?

Answer 1

no its not equal its less.

Answer 2

It tends to one. The farther you go with the decimal, the closer it gets to one. :P I guess you could say it's one. since: 1/9 is .111111 repeating, 2/9 is .2222222 repeating, 3/9 is .333333... and so one. 9/9 is equal to 1, though. So I guess one could argue it equals to one.

Answer 3

it is in fact equal to 1

1/9 =.11111111

2/9=.22222222

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.

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8/9= .8888888888

9/9=1=.999999999999

Answer 4

yes it is equal to 1 any calc teacher will tell you that

anyone who says otherwise is wrong

Answer 5

Yes, it is equal to one.

Answer 6

Depends on your reference.  Most of the time they will say it is equivalent to 1 instead of equal to 1.  If you need to estimate or whatever, definitely use the 1

Answer 7

Look at it this way:

1/9 = .111111(repeating)

2/9 = .222222(repeating)

3/9 = 1/3 = .333333(repeating)

4/9 = .444444(repeating)

5/9 = .555555(repeating)

6/9 = 2/3 = .666666(repeating)

7/9 = .777777(repeating)

8/9 = .888888(repeating)

9/9 = ???/3 = .????

What's the pattern, and what do you think?

Answer 8

Yes, because 0.9999... is equal to 9999/9999 ir 999/999 or 99/99 or 9/9 or 1/1

There is one way of changing repeating decimals to fractions..

Answer 9

it same

.999 repeating = 1 yeah its true

Here is proof

.first way to prove

prove: you know (1/3) = .333 repeat, right?

time 3 both sides

3(1/3)= 3(.333 repeat)

1 = .9999 repeat( prove)

2. second way to prove by series

.999 repeat = .9 +.09+ .009 +.0009 ......... so on., right

that is geometric serie i dont know you have ever heard that before

sum for this serie will be = a1/(1-r)

a1 is the first term, r = second term divide first term , or third term/ second so on.........

a1= .9 , r = .09/.9 = .1

sum .999 repeat = .9/(1-.1) = .9/.9 = 1( approve)

if in mathematic or engineering that is true statement

.999 repeat is equal 1

3. third way to prove

.999 .....( repeat)

time 9 both sides

9 * 0.999... and 9= 10-1

= (10 - 1) * 0.999... distribute

=9.999... - 0.999... = 9

therefore 9*(0.999....)= 9

divide 9 both sides

.9999..... = 1 (prove)

4. we dont know what is .9999 ... = to?

let x = .9999.....

time 10 both sides

10x = 9.9999... repeat

subtract x both sides

10x-x = 9.999 .... - x

9x = 9.999... -x

but we let x= .99999......

9x = 9.999.... - .9999....

9x = 9

divide 9 both sides

x= 1

prove!!!

Answer 10

Not equal, because the only number that has the same value as 1 is one itself.  There's just an eensy teensy bit less than one though.

Answer 11

No, it is not 1. The notation for 1 is .... 1.

Simple as that

.9999etc may be as close as you can get to it and still less than one.

It is just not the same. You might as well feel sorry for 99 that it is nearly 100, but it isn't. 99 is 99, and 100 is 100.

Answer 12

technically, no it's not

Answer 13

yes, 0.999999... = 1

think of 1/3  =  0.333333...

3 * 1/3  = 1

hence  3 * 0.333333...  = 0.999999... = 1

Answer 14

Yes

Given:

10x = 9.99999...

Then x= .99999....

10x-x=9x

9x=9

x=1

QED

Answer 15

No it is not equal to one because it is .9repeating

you cant change it

Answer 16

It will never equal 1.  1 is 1, and that's it.

Answer 17

It's equal to 1 if it repeats forever (infinite decimal)

Answer 18

its only equal to one if u round it, so yes