Is anyone able to calculate the pH of this mixture...?

Question

10mL of 0.025 M HCl when diluted to 50mL to solution

Answer 1

M  =  0,025 /5

     = 0,005  (Hydrogen ion concentration)

log 0,005  = - 2.301

pH   =  2,3

Answer 2

10 ml x 0.025 M = 50 ml (X M)

X = 0.005 M HCl = 0.005 M H+ = 5 x10^-3 M H+

pH = -log [H+] = -log 5x10^-3M

pH = 2.3  Answer