Is anyone smart enough to figure this ridiculous algebra 2 homework out ??

Question

these are my last 11 problems outs of 60 please help i dont get math at all :( my second day and im going to fail !!!!

Solve each equation. Check your answers.

#7: 5c - 9 = 8 - 2c

#13: 6(t - 2) = 2(9t - 2)

#15:4(k + 5) = 2(9k - 4)

Solve each formula for the indicated variable.

21. S = 2prh, for r

Solve each equation for x. Find any

restrictions.

#27: x-2/2 =m+n

Write an equation and solve each problem.

31. Geometry The length of a rectangle is 3 cm greater

than its width.The perimeter is 24 cm. Find the

dimensions of the rectangle

33. Geometry The sides of a rectangle are in the ratio 3 : 2.What is the length of

each side if the perimeter of the rectangle is 55 cm?

Solve each formula for the indicated variable.

45. h = vt - 5t2, for v

53. Find 4 consecutive odd integers with a sum of 184.

Solve for x. State any restrictions on the variables.

59. c(x + 2) - 5 = b(x - 3)

61. b(5px - 3c) = a(qx - 4)

Answer 1

Algebra really is not all that difficult as long as you:

1.) figure out what the question is asking/ figure out what you are looking for

2.) take each problem step-by-step

7.) 5c - 9 = 8 - 2c; in this problem they want you to solve for variable c.

The first thing you are going to want to do is combine common terms.

Your two common terms are the number values (9 and 8), and the variables 5c and 2c.

5c - 9 = 8 - 2c

add 2c to both sides

5c + 2c - 9 = 8 - 2c + 2c

7c - 9 = 8

Now add 9 to both sides

7c - 9 + 9 = 8 + 9

7c = 17

Divide both sides by 7

7c/7 = 17/7

c = 17/7 or 2.4286

13.) 6(t - 2) = 2(9t - 2); in this problem, they want you to solve for the variable t.

The first thing you are going to want to do is apply the distributive property to both sides of the equation. Therefore multiply the 6 through the (t - 2) on the left, and multiply the 2 through the (9t - 2) on the right.

6(t - 2) = 2(9t - 2)

6(t) - 6(2) = 2(9t) - 2(2)

6t - 12 = 18t - 4

Now combine common terms like you did in question 7. Your common terms here are the numbers (12 and 4) and the variables (6t and 18t).

6t - 12 = 18t - 4

add 12 to both sides

6t - 12 + 12 = 18t - 4 +12

6t = 18t + 8subtract 18t from both sides6t - 18t = 18t - 18t + 8

-12t = 8divide both sides by -12

-12t/-12 = 8/-12

t = -2/3

15.) 4(k + 5) = 2(9k - 4); you are going to do this problem the same way you did the last one. Again, they want you to solve for the variable k.

First, use the distributive property on both sides of the equation, so that 4 is multiplied through (k + 5), and 2 is multiplied through (9k - 4)

4(k + 5) = 2(9k - 4)

4(k) + 4(5) = 2(9k) - 2(4)

4k + 20 = 18k - 8

Now combine common terms. Your common terms (for this equation) are the numbers (20 and 8) and the variables (4k and 18k).

4k + 20 = 18k - 8

Subtract 4k from both sides

4k - 4k + 20 = 18k - 4k - 8

20 = 14k - 8

Add 8 to both sides

20 + 8 = 14k - 8 + 8

28 = 14k

Divide both sides by 14

28/14 = 14k/14

2 = k

All of the previous three questions asked you to check your answers. You can do this one of two ways.

1.) You can put the variable back into the original equation and see if the left side = the right side.

So for problem 15 you would plug the answer of 2 into every k.

4(k + 5) = 2(9k - 4)

4((2) + 5) = 2(9(2) - 4)

4(7) = 2(14)

28 = 28

Because the left and the right side = the same amount, you know that 2 is the correct answer.

2.) You can graph the two lines and see when they intersect.So for problem 15 you would graph:

4(k + 5), and

2(9k - 4)

Then you would see when the two points intersected. If they intersect when k = 2, then 2 is the correct answer.

21.) S = 2prh, for r; in this question they want you to solve the entire equation for r. In other words, they want you to have an answer that says r = whatever.

To do this you are going to try and isolate r to one side, one step at a time.

S = 2prh because the entire problem is a mulitplication you can simply divide both sides by all variables and numbers besides r.

S/2ph = 2prh/2ph

S/2ph = r

Or, you can divide each separate term one at a time.

S = 2prh

Divide both sides by 2

S/2 = 2prh/2

S/2 = prh

Divide both sides by p

S/2p = prh/p

S/2p = rh

Divide both sides by h

S/2ph = rh/h

S/2ph = r

Either way you get the same answer.

27.) x-2/2 =m+n; the instructions told you to solve for x, so try to isolate x to one side of the = sign.

x-2/2 =m+nFirst of all, simplify (2/2) = 1

x - 1 = m + nNow add 1 to both sides

x - 1 + 1 = m + n + 1

x = m + n + 1

I am not positive what restrictions the question is refering to except maybe that m cannot = n because they are different variables, and m + n + 1 cannot be > or < x.

31.) Find the dimensions of a rectangle whose perimeter = 24 cm and whose length is 3 cm greater that its width.

So,

P = 24 cm

l = 3 + w

The equation for finding the Perimeter of a rectangle is

P = l + w + l + w

P = 2l + 2w

You know that your P = 24, so substitute that in first.

24 = 2l + 2w

You also know that every l = 3 + w, so substitute that in as well.

24 = 2(3 + w) + 2w

24 = 6 + 2w + 2w

24 = 6 + 4w

Subtract 6 from both sides

24 - 6 = 6 - 6 + 4w

18 = 4w

Now solve for w and l. W will be the easiest to find.

18 = 4w

Divide both sides by 4

18/4 = 4w/4

9/2 = w

Because l is 3 + w, l =

9/2 + 3 = l

9/2 + 6/2 = l15/2 = l

Now, check to make sure your w's and l's add up.

24 = 2w + 2l

24 = 2(9/2) + 2(15/2)

24 = 9 + 15

24 = 24

It does so the dimensions of your rectangle are 15/2 cm, 9/2 cm, 15/2 cm, 9/2 cm.

33.) This question is a little harder. What it is saying is the sides of the rectangle are 2w and 3l. Solve for w and l respectively, to make the equation a little easier.

2w = 3l

2w/2 = 3l/2

w = 3l/2

2w = 3l

2w/3 = 3l/3

2w/3 = l

Now you know P, l, and w. Plug them into the perimeter equation for a rectangle and begin