Is there any one good at maths??

Question

i need some help for a few questions like eg 2(over)x+2 + 3(over)2x+1

an msn hotmail would be great i need some one to tell me what to do not an answer but an explaination!

Answer 1

2/x +2 +3/2x+1?

2+1 = 3

2/x+3/2x+3 =

4/2x+3/2x +3 =

7/2x+3

denominators must be the same to add them

or

2/(x +2) +3/(2x+1)?  this problem is different.  you should type the question exaclty as it appears in the book and with paranthesis so we know what is togheter and what isn't... also i would think you need help with the english too.  its math or mathematics not maths.

Answer 2

No but I am very good a grammar

Answer 3

The Answer is (7x+8) over (2x+1)(x+2). I'm Really good at math so if you need any other answers I'll try to answer them.

Answer 4

You just add them on the numerator and the denominator ex the numerator of your question would equal 5 and denominator is 3x+3. answer is 5 over 3x+3.

Answer 5

i forgot how to do it but i know the first step is to make the denominators the same...

Answer 6

It's simple But that would be cheating.

Answer 7

what are you asked to do? simplify?

if it is simplify then just find a common denominator like you always do when adding fractions. in this case the common denomnator would be (x+2)(2x+1)

if this is still really confusing email me if you like.

[e-mail]

Answer 8

I think you have to factor out the 2x+1  

Answer 9

= 2/(x + 2) + 3/(2x + 1)

= (2[2x + 1] + 3[x + 2])/([x + 2][2x + 1])

= (4x + 2 + 3x + 6)/([x + 2][2x + 1])

= (7x + 8)/([x + 2][2x + 1])

Answer: (7x + 8)/([x + 2][2x + 1])