It takes 220 cal to raise the temperature of 360 g of lead from 0 to 20 degrees C.?

Question

What is the specific head of lead in kcal/(kg K)?

Answer 1

specific heat = Energy/mass/Temp = 220 cal/((0.360kg)*(20+273.15-0+273.15))

specific heat = 30.556 cal/kgk * 1kcal/1000cal = 0.030556 kcal/kgK is the final answer

Answer 2

0.030555 kCal/kgK  

Specific heat is how many kcal it takes to heat a kg by 1 degree K.  

It took 0.22 kcal to heat 0.36kg by 20 Degrees (K and C are on samel scale)

so = 0.22 kcal / 20 K / 0.36 kg  = 0.030555 kcal/ kgK