Java code (explain only..)

Question

Given x = 1, y = 2, what is the output of the following code?

if (x != y)

System.out.print ("Statement 1. ");

else

System.out.print ("Statement 2. ");

System.out.print ("Statement 3. ");

Answers are statements 1 & 3.

Hmm, why is it statement 3? Is it because there is a semi-colon after the statement 2 so it prints out statement 3 as well? I think it should just print out statement 1 since x != y is true...

Answer 1

The else includes the one statement after it much like the if so statement 3 is not part of the if/else and thus is always printed.

Answer 2

Your code can be re written as

if (x != y)

{

System.out.print ("Statement 1. ");

}

else

{

System.out.print ("Statement 2. ");

}

System.out.print ("Statement 3. ");

Reason being if AND else both will consider next line within their scope by default.

So,Third one is independent of IF AND ELSE.

In any case 3 will be printed along with 1 and 2 depending upon condition provided in IF()