Question:

Joey drove the car and covered distance of 28m 35 degrees North of East, then turned 3 km Northwest?

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Find the car's resultant displacement vector. Thank you very much!

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  1. Assuming you meant 28 km N of E,

    North displacement = 28sin35 + 3sin45

    East displacement  = 28cos35 - 3cos45

    North displacement ≈ 16.46073 km

    East displacement  Ã¢Â‰Âˆ 20.81494 km

    26.89410 km @ 37.73841 N of E

    or

    26.9 km @ 37.7 N of E

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