Question:

Juan goes to a bank to get change for a $50 bill consisting of all $5 bills and $1 bills. ?

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How many of each kind are there? I have tried to figure this out and I cannot

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  1. $35 in 5's and $15 in 1's


  2. Well you could get 25.00 in 5.00 bills and 25.00 in one dollar bills, you could get 45.00 in 5's and 5.00 in ones, there are a lot of different things you could do.  

  3. He would either have fifty $1, or ten $5.  He could have nine $5, and five $1.  This can be figured in many ways.  



  4. so 22 bills = (7 pcs 5$ and 15pcs 1$)

    7 pcs x (5$) = 35$

    15pcs x (1$) = 15$

    35$+15$=50$


  5. Thats easy fifteen $1.00 bill plus 7  $5.00 bills

    7 times 5,00 = 35.00 +1 times 15.00=15.00 = atotal of 50.00

  6. Pretty easy.

    5 x 7 = 35

    1 x 15 = 15

    35 + 15 = 50

    7 $5 bills

    15 $1 bills

  7. you can use the tabulation method. just trial and error.

    IF YOU TAKE 6 $5 bills -- $30

    then $1 bills will be -- 22 - 6 = $16

    $ (30+16)= $46

    so this is wrong.

    lets try

    7 $5 bills --- $35

    means 22-7=15

    15 $1 bills.=$15

    $35+$15= $ 50 --- BINGO

    so ans is : 7 --$5 bills

                     15-- $1 bills.

    hope you understand =)

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