Kinematics question?

Question

A daring ranch hand sitting on a tree limbwishes to drop vertically onto a horse galloping under the tree. The constant speed of the horse is 10 m/s, and the distance from the limb to the level of the saddle is 3.00m.

What must be the horizontal distance between the saddle and limb when the ranch hand makes his move?

How long is he in the air?

Answer 1

The constant speed of the horse is 10 m/s, and the distance from the limb to the level of the saddle is 3.00m.

2.) How long is he in the air?

Δx = vo Δt + ½ a Δt² ; a = gravity

Δx = 3.00m ; Δt = ?; vo = 0

3 = 0 + 9.8 / 2 Δt²

3 / 4.9 = Δt²

t = 0.78 s

1.) The horizontal distance between the saddle and limb?

How far does the horse travel in t seconds?

v = 10 m/s; t =  0.78 s

10 *  0.78 = 7.8 m