Late Night Integer Question...Please Help!?

Question

Problem: Find for consecutive integers such that 4 times the sum of the first and fourth is greater than 24 times the third.~ Thanks in Advance!

Answer 1

the question is incomplete ...greater by what amount?

one thing i know 4 sure is that the numbers are negative.

Answer 2

4(x+(x+3))>24(x+2)

8x+12>24x+48

-36>16x

x<-2.25

since the next lowest integer is -3, the numbers are -3, -2, -1, and 0