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Let f(x) = ln rad((8x-7)/(7x+8)). Then f '(x) = ?

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Can anyone help me and include step-by-step procedures? Thank you!

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  1. if by ' rad' you mean square root, then f(x) = [1/2] ( ln (8x-7) - ln (7x + 8) ) so f '(x) = [1/2] ( 8 / [8x-7] - 7 / [ 7x + 8 ] )

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