Lim[x --> 0] sin(cosx)/secx?

Question

Lim[x --> 0] sin(cosx)/secx?

Answer 1

sin1 in the answer

Answer 2

cos(0) = 1 and sec(0) = 1, so this just becomes sin(1).

Answer 3

Lets do the bottom first:

secx = 1/cos x cos (0) = 1

so s*x(0)= 1

Then the top:

cos (0)=1

then the equation become sin(1)/1 or sin(1)