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a 12 liter is 60% alcohol. If 8 liters of a 25% alcohol mixture are added, what percent will be formed?

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  1. [(12 x 0.6) + (8 x 0.25)]/(12 + 8)

    [7.2 + 2]/20

    9.2/20

    0.46

    Answer: 46%


  2. U have 12*0.6=7.2 l of pure alcohol in 12l

    Also u have  8*0.25=4l of pure alcohol in 8l

    Mixing u have 7.2+4=11.2 l of pure alcohol in 20 l (100%)

    It will be formed 11.2*100/20=56%

  3. 60% of 12 liters is 7.2 liters of alcohol.

    25% of 8 liters is 2 liters of alcohol.

    So there will be 9.2 liters of alcohol in a 20 liter mixture.  To get the percentage, divide: 9.2 / 20 * 100% = 46%

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