Linear application help?

Question

a 12 liter is 60% alcohol. If 8 liters of a 25% alcohol mixture are added, what percent will be formed?

Answer 1

[(12 x 0.6) + (8 x 0.25)]/(12 + 8)

[7.2 + 2]/20

9.2/20

0.46

Answer: 46%

Answer 2

U have 12*0.6=7.2 l of pure alcohol in 12l

Also u have  8*0.25=4l of pure alcohol in 8l

Mixing u have 7.2+4=11.2 l of pure alcohol in 20 l (100%)

It will be formed 11.2*100/20=56%

Answer 3

60% of 12 liters is 7.2 liters of alcohol.

25% of 8 liters is 2 liters of alcohol.

So there will be 9.2 liters of alcohol in a 20 liter mixture.  To get the percentage, divide: 9.2 / 20 * 100% = 46%