Logarithm, square root equivalence?

Question

No need to show me the way, just give me answer

1) Xlog 2^(1/2) = -2 1/2

Find x!

2) ____1____ - _____1_____ - _____1______ =

.....10/9log 4......24/25 log 4.......125/216 log 4

3) 0.04 log M + 0.2 log M^2 = 1 1/4

Find M!

4) (a+b) (____ab^ -1_-_ba^ -1_____)

..................( ab^-1 + 2 + ba^-1 )

Find the final a & b relation! eg. (a+b)^2

5) sqrt[17^(1-x)] = 1/3 [sqrt(9^(4-x)]

Find x!

6) log 2 =x log 3=y

log [ sqrt(4^1/3) . sqrt(15)] = ?

7) 1/5log 64 . 27log [sqrt(125)] . 4log [1/3.sqrt(3)] + [sqrt(2). 2log 9] =

[ 9 . 27log 8 ]

8) log 5 = p log 7 = q

7^(x+1) = 5^(2-x)

xlog y = z

x is the basis

sqrt(x)= x^(1/2)

___4___ = 4/2

.....2.

2^(2+1) = 2^3

Answer 1

I would have helped you if you asked how to solve these and not just the answer, but it is obvious that you don't even want to learn how to deal with that kind of math problems so I don't think anybody's gonna help you.

Answer 2

what is the use of an answer if you don't know how to do it?

You may pass some stupid test but you will remain ignorant.

At least try !!

Answer 3

do your own homework!  

A new school year and HERE we GO again!

Answer 4

You should probably consider formatting your problems in a way that would allow us to comprehend them.  ASCII doesn't lend itself well to mathematical formulas.  As such we need the liberal use of parentheses in order to make our problems clear.  For example, your first one...

Is part on the left [x * log10(2^(1/2))] or is it [x * (log10(2))^(1/2))] or possibly [(x * log10(2))^(1/2)]?  All three interpretations are valid, but all three give different results.