Question:

Log(base of 2) (x^2 + 3x-2) = 3?

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solve for x.

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4 ANSWERS


  1. x² + 3x - 2 = 8

    x² + 3x - 10 = 0

    (x + 5)(x - 2) = 0

    x = - 5 , x = 2


  2. 2^3 (x^2 + 3X-2) = 3

    8 (x^2 + 3x-2) = 3

    (x^2 + 3x-2) = 3/8

    x = 0.65

  3. 2^3 = x^2 + 3x - 2

    8 = x^2 + 3x - 2

    x^2 + 3x - 10 = 0

    (x + 5)(x - 2) = 0

  4. 2^3=x^2 + 3x -2

    x^2 +3x-10=0

    (x+5)(x-2)=0

    x=-5 or x=2

    ANSWER

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