Question:

Logic gate question! 2 input 2 output table, create circuit?

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So I need a circuit for this table:

input output

00 00

01 01

10 10

11 00

please create and explain the circuit?

(I know it's pretty hard to draw out)

if able, use all NAND gates?

Thank you so much- <3

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4 ANSWERS


  1. You are supposed to do K-maps and figure out the equations. Our helping doesn&#039;t really help you, but let&#039;s walk through it anyway. Any function can be made from NAND gates.

    Let&#039;s label the inputs A and B, the outputs C and D.

    From the table, C and D both equal 1 only for one set of inputs. These are obvious applications for an AND gate.

    So, C equals A AND (NOT B). To get NOT B, put B into both inputs of the NAND gate. Then, use NAND gate for A and output of this gate. Finally, result is inverted, so put it to both inputs of 3rd NAND gate to invert it back.

    Similar process for D. You need NOT A AND B. So, invert A by putting it to both inputs of a NAND. Then, NAND this and B. Finally, since inverted, put output from 2nd gate to both inputs of NAND to invert back.

    Totals: 3 gates for each output, 6 total.


  2. 6 NAND gates are required for the XOR w/ two outputs:

    Use the following NAND gate XOR to start:

    http://www.play-hookey.com/digital/xor_f...

    Then add 2 NAND gates on the output of the above 4 NAND gate XOR.

    The output of the 4-NAND gate XOR tie to one input on each of the two NAND gates -- then tie input A to one of the two output NAND gates and tie input B to the other NAND gate input.

    I hope this helps

  3. this will absolutely require that i design the whole thing, right? sorry, i cant embed pics. what you have is an logic array where, if both inputs are different, the output is the same as the input. this is not a gate if a gate has two inputs and two outputs IT IS NOT LOGIC BECAUSE IT DOES NOT MEET THE DEFINITION OF A MACHINE. to draw this place the input of the system in series with the output through a BJT (input on the collector, output on the emitter). tie the base to ground through a resistor. next, run the inputs parallel to the above circuit into an XNOR gate (it take like 16 NANDs to make an XOR gate, which you should be able to find on the internet pretty easily. just add a NAND gate with the outputs shorted Behind the XOR to get an XNOR)

    use the XOR outputs to turn on both BJTs simultaneously by connecting each of the outputs to the base of the BJTs( each base gets its own output, no shorting). when the inputs are not different, the BJTs are not triggered, and the voltage flowing to their base is bleed off by the resistors to ground. when the inputs are dissimilar, the output of the XNOR will be able to fire the transistors because the resistors to ground will prevent the system from shorting out.

    it is up to you to understand the system and draw it i dont do homework. just remember, when the inputs are dissimilar the output is the same as the inputs

    best of luck emily

    i am so tired of this question.

  4. It&#039;s an XOR, if you only have one output

    output is high if either input is high but not both.

    http://en.wikipedia.org/wiki/XOR

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