MATH HELP? Equation?

Question

1. Find an equation of the line containing the given pair of points.

(1,3) and (3,4) y= ?

2. Find an equation of the line having the given slope and containing the given point.

m= 7/8, (5,-2)

3. Find the slope if it exist 3x-10y=20

Answer 1

1. y=mx+b

where m= (Y2-Y1)/(X2-X1)

m= (4-3)/(3-1) = 1/2

y=1/2x+b

Substitute your points in....

3 = 1/2*1 + b

Solve for b

b= 5/2

Therefore the answer is...   y = 1/2x + 5/2

2.y=mx+b

5 = 7/8*(-2) +b

b= 27/4

Answer...  y = 7/8x + 27/4

3.

Put in form y=mx+b

y = (3/10)x - 2

Since m is the slope.... the answer is 3/10

                

Answer 2

1. the slope is

   4-3/3-1 = 1/2

y = (1/2) x + b

you substitute  (1,3) and (3, 4) for x, y

  (1)  3 = (1/2) (1) + b

         b= 5/2

  (2) 4 = (1/2) (3) + b

     b=5/2

so 1.  y=(1/2)x + 5/2

2. y=(7/8)x + b



substitute (5,-2) for x, y



  -2=(7/8)(5) + b

b= -51/8

  

so y= (7/8)x -51/8

3. 3x-10y=20

    3x-20=10y

    y= 3/10x -2

so, the slope is 3/10

　

　

Answer 3

3. slope = 3/10

Answer 4

I can only answer your #3 question; here is how to find the slope:

10y/10=-3x/10+20/10

y=3x+2

the last pat is the slope.

Answer 5

1. To solve this, you need to use the point-slope form: y-y1 = m(x-x1)

simply substitute one point for y1 and x1.

so (y-3)=m(x-1)

to figure out the slope you do y2-y1/x2-x1

which in this case would be 4-3/3-1 which is 1/2, so the slope is 1/2.

and the equation is (y-3)=1/2(x-1)

2. this is easy, substitute the numbers in point-slope form.

(y+2)=7/8(x-5)

3. you need to make this in slope-intercept form, and you do that by isolating the y first.

-10y=-3x+20.

then you divide both side of the equal sign by -10 and you get

y=(3/10)x - 2