MATHS QUESTION = Use Pythagoras' theorem to find the diagonal of a square of side 10cm?

Question

MATHS QUESTION = Use Pythagoras' theorem to find the diagonal of a square of side 10cm?

Answer 1

Pythagoras' theorem is a^2+b^2=c^2

So, you have to find out what √(10^2+10^2) is.

√(10^2+10^2) = √(200) = 14.14213562.. = 14.14 cm (2dp)

Answer 2

By Pythagoras Theorem

x^2 = 10^2 + 10^2

x^2 = 100 + 100

x^2 = 200

x=10 sq rt 2

Diagonal of a square can also be found out by using Sq rt 2 * side of square

Answer 3

Pythagorean Theorem: in a right triangle, (leg 1)^2 + (leg 2)^2 = (hyp)^2

Draw a square and its diagonal, and you will notice that the diagonal forms a right triangle with two of the sides.

Thus, D = sqrt(10^2 + 10^2) = 10sqrt(2)

Answer 4

diagonal

= sqrt(10^2 + 10^2)

= sqrt(10^2 * 2)

= 10 sqrt(2)

Answer 5

Let x be the length of diagonal.

Then you have a right-angled triangle with side lengths 10, 10, and  x  where x is the hypothenuse

By Pythgoras' theorem

x^2 = 10^2 + 10^2

x^2 = 100 + 100 = 200

x = √200 = 10√2