Question:

MJ's vertical leap is reported to be 48 inches. what's his takeoff speed in m/s?

by  |  earlier

0 LIKES UnLike

MJ's vertical leap is reported to be 48 inches. what's his takeoff speed in m/s?

 Tags:

   Report

1 ANSWERS


  1. v^2 = 2*g*y

    v^2 = 2*(9.8m/sec)*48in*(1m/39.4in)

    v^2 = 23.878 m^2 / sec^2

    v = 4.9 m/sec

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.