Question:

Magnetic flux?

by Guest44528  |  earlier

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A square loop 1.70 m on a side is placed in a magnetic field of magnitude 0.400 T. If the field makes an angle of 49.0° with the normal to the plane of the loop, find the magnetic flux through the loop.

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  1. Φ = BA cos θ

    = 0.400 T x (1.70 m)² x cos(49.0°)

    = 0.758 Wb

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