Magnetic force problem?

Question

A cosmic ray proton moving toward the earth at 5.00 *10^7 m/s experiences a magnetic force of 1.70 *10^-16 N. What is the strength of the magnetic field if there is a 45 degree angle between it and the protons velocity?

Answer 1

F=qvBsina;F is the force;v is the rate ;B is the amount of magnetic field and sina is the angle between the magnetic field and the way it moves.1.70*10^-16N=1.6*10^-19 *5.00*10^7*B*sin45