Magnitude of Electrical Force.?

Question

The nucleus of a gold atom has a charge quantum number of +79. An alpha particle (helium nucleus) has a charge quantum number o f +2. For this problem neglect the electrons surrounding the nucleus of each atom.

a) what is the magnitude of the electrical force of the gold nucleus on the alpha particle when it is 1.00 x 10^14 m from the nucleus?

b) what is the magnitude of the electrical force of the alpha particle on the gold nucleus when the alpha particle on the gold nucleus when the alpha particle is at the same position as in part a).

Answer 1

F = kq1q2/r^2, where k = 9.98755E9 N-m^2/C^2 and q = 1.602177E-19 C per quantum.

F = 364.519 N.

F is the same for questions A and B.

Answer 2

F = k(q1)(q2)/r^2

1.  k is from your textbook

2.  make sure your units match so you don't get a bizarre answer.