Math 5 help will pick ba-10pt?

Question

suppose sin(x)=9/11 and that 90degrees < x<180 degrees

find cos(x) and tan (x)

thanks

Answer 1

cosx= sqrt(1-sin^2x)=sqrt(1-81/121)=sqrt(40/12...

or cosx=6.32/11=0.57

tanx=sinx/cosx=(9/11)/0.57=0.818/0.57= 1.435

Answer 2

sin(x)=9/11

opposite/hypotenuse=9/11

opposite = (9/11)hypotenuse

opposite² + adjacent²=hypotenuse²

adjacent = sqrt(11²-9²)

             = sqrt(40)

cos x= adj/hypo

          but as we are in the second quadrant cos is negative

tanx= oppo/adj

         Here as we are in the second quadrant tan is negative