Math algebra problem?

Question

can someone please help me how to solve these because i'm starting to get really confuse and please show your work thank you

5-2*3+3^2+1)

and

6-2(4+5)+6

Answer 1

can i phone a friend?

Answer 2

BEDMAS (this is the BASIC/BASE of many algebraic equations and problems...it demonstrates in which order problems need to be solved)

Brackets

Exponents

Division/Multplication

Addition/Subtraction

here we go:

did u miss an opening bracket in the first problem? that would make a difference...but I'll solve it anyways

5-2*3+9+1

5-6+9+1

9

6-2(9)+6

6-18+6

-6

if u have more questions email me at [e-mail]

Answer 3

9

-6

Answer 4

5-2*3+3^2+1

5-2*3+9+1

5-6+9+1

9

6-2(4+5)+6

6-2(9)+6

6-18+6

-6

Answer 5

5-2*3+3^2+1

=5-6+9+1

=-1+9+1

=9

6-2(4+5)+6

=6-8-10+6

=-6

Answer 6

Use B>E>D>M>A>S! Solve in order and you will come up with the right answers.

Brackets

Exponents

Division

Multiplication

Addition

Subtraction

Answer 7

1.)    5-2*3+3^2+1 could also be written as 5-2x3+(3)(3)+1, therefore

        5-2X3+9+1

        5-6+10

        -1+10

        9    Answer

2.)    6-2(4+5)+6  Do the ones in the parenthesis first;

        6-2(9)+6      Also, 6-8-10+6 (multiplying -2*4 & -2*5 !

        6-18+6                                                -8-10 = -18

        -6  Answer

Answer 8

First do the Stuff in the brackets then you always multipy and divide first, secondly you add and subtract.

3^2=3*3

2*3=6

5-2*3+3^2+1

5-6+(3*3)+1

5-6+9+1

-1+9+1

9