Math equation...please help me?

Question

A person stands 35.0 m from a flag pole. With a protractor at eye-level, he finds that the angle the top of the flag pole makes with the horizontal is 25.0 degrees. How high is the flag pole? (the distance from his feet to his eyes is 1.70m)

Answer 1

i dont have a calculator...so just punch this in:

flagpole height = tan(25)*35 + 1.7

Answer 2

flag pole is {1.70m + 35.0tan(25deg)m} = 18.02m

Answer 3

Tan(25°)=X/35

           X=(35m)(Tan(25°)=35(0.46631)m

           X=16.32m

      Total high of the flag pole is (16.32+1.7)m

      Total High=18.02 m

      

Answer 4

Tan of 25 is pole height over distance, so

tan 25 = h/35

h = 35 tan 25 = 16.3

add the 1.7 to get 18 m

.

Answer 5

So you have a right triangle, base 35.0 m, acute angle 25.0 degrees.

So the other angle must be 90-25 or 65 degrees.

If length of sides is proportional to opposite angles,

then X/25=35/65 or X = 25*35/65 therefore 13.46.

Add 1.70 to get true height of pole = 15.16

Answer 6

Good 'ole Geometry. Draw it out, it makes a triangle, and do either sin, cos or tan depending on your missing side. Good luck.