Question:

Math help please? Not sure I am getting this. ?

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y^2-6y+9 /////// y^2-9

________ //divide /// ________

-(y^2-4) /////// y^2-8y+12

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  1. I cannot understand. there is a lot of decoration there. The main problem cannot be understood! Well use the following if you can!

    y^-6y+9 = (y-3)^2

    y^2 -9= (y-3)(y+3)

    y^2 - 4 = (y-2)(y+2),

    y^ - 8y +12 = (y-6)(y-2)

    (a/b)/(c/d) = ad/bc.


  2. (y^2 - 6y + 9)/-(y^2 - 4) ÷ (y^2 - 9)/(y^2 - 8y + 12)

    = (y^2 - 3y - 3y + 9)/-(y^2 + 2y - 2y - 4) * (y^2 - 2y - 6y + 12)/(y^2 + 3y - 3y - 9)

    = (y - 3)(y - 3)/-(y + 2)(y - 2) * (y - 2)(y - 6)/(y + 3)(y - 3) (cancel out y - 3 , y - 2)

    = (y - 3)/-(y + 2) * (y - 6)/(y + 3)

    = (y - 3)(y - 6)/-(y + 2)(y + 3)

  3. your question is not clear

    Factorise all terms

    and get the answer

    for eg  factor of y^2-6y+9 = (y - 3)(y - 3)

                           y^2 - 9    = (y-3)3(y+3)

                            y^2 -4  = (y+2)(y-2)

                             y^2 - 8y +12  = (y-2)(y-6)

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