Math help...?

Question

One of the most rapid increases in temperature occurred on January 22, 1943, in the town of Spearfish, South Dakota. Within 2 minutes, the temperature increased 49°F.

a.What was the change in temperature in degrees Celsius?

b.The temperature of the air after the 2 minutes had passed was 45°F. What was the starting temperature in degrees Fahrenheit?

c.What were the starting and final temperatures in degrees Celsius?

please if you can tell me how you got that answer ten points

Answer 1

b. 45 - 49 = -4 Fahrenheit

c.Starting temp. in C -> -4 - 32 x (5/9) = -36 x (5/9) = -180/9 = -20 Celsius

Final temp. in C -> 45 - 32 x (5/9) = 13 x 5/9 = 65/9 = 7 2/9 C

a. The change in temp. -> Final - starting  = 7 2/9 - (-20) = 27 2/9 Celsius

Answer 2

Tc = (5/9)*(Tf-32)

a)Tc=(5/9)(49-32)

       =5/9(17)

       =9.4444444444

b)45-49=-4

c)starting

   (5/9)(-4-32)

   (5/9)(-36)

    -20

final(5/9)(45-32)

   (5/9)12

    6.6666666666666666