Math homework help! word problem!?

Question

The length of a rectangle sign is 10ft. less than twice its width. Its perimeter is 118 ft, Find the length and width.

Answer 1

Set up equations to express the facts you know, in terms of the unknowns

L = length

W = width

If the perimeter is 118 feet, then we can say

2L + 2W = 118

Cool?

And we also know that

L = (2W - 10) (2 times the width, and minus 10 feet)

So plug the above into the first equation, substituting L

2(2W - 10) + 2W = 118

Expand out the brackets

4W - 20 + 2W = 118

And if we combine the Ws....

6W - 20 = 118

6W = 138

Divide both sides by 6

W = 23

And if that's true, then

2L + 2W = 118

2L + 46 = 118

2L = 72

L = 36

Done!

Answer 2

Length=36 ft.

Width=23 ft.

Answer 3

homework is for you to do