Math ii Question and Answer?

Question

Acme car rental agency charges a fee of $29 per day plus $0.15 per mile.travel Ease car rental agency charges $20 per day plus $0.25 per mile.For a one-day, what Mileage would make the two rates equal?

10 points....

Answer 1

Make the questions equal to each other to solve.

20 + 0.25x = 29 + 0.15x

0.10x         = 9

x               = 90

A mileage of 90 would make the two rates equal for a one day rental.

Answer 2

I seriously dont know that question hurts your brain just reading it

Answer 3

29 + .15m = 20 + .25m

9 = .10m

m = 9/.10 = 90

90 miles will produce equal rates for one day

check:

Acme: 29 + .15(90) = 29 + 13.5 = 42.50

TravelEase = 20 + .25(90) = 20 + 17.5 = 42.50

The rental will be 42.50 for each at 90 miles

Answer 4

algebraically set up a system of equations

solve them and your answer is the number of days

Answer 5

29 +.15m = 20 +.25m

9 = .10m

90 = m

90 miles

Answer 6

The answer is 90 miles.  From the equation below, let x be equal to the mileage:

29 + 0.15x = 20 + 0.25x

Transpose to group similar terms:

29 - 20 = 0.25x - 0.15x

9  = 0.1 x

x = 9/0.1

x = 90

If you want to check:

$29 + $0.15 (90) = $42.5

$20 + $0.25 (90) = $ 42.5

Answer 7

if we travel x miles a one-day,

then the rate for Acme car rental agency will be :

29+0.15x

the rate for Ease car rental agency will be :

20+0.25x

29+0.15x=20+0.25x

9=0.1x

x=90

90 miles would make the two rates equal

Answer 8

daily costs, "x" being the number of miles

Acme: 29 + 0.15x

Ease: 20 + 0.25x

equation to use:

29 + 0.15x = 20 + 0.25x

29 - 20 = 0.25x - 0.15x

9 = 0.1x

9 = (1/10)x

9*10 = 90 = x

90 miles

Answer 9

90 miles..

29+.15x=20+.25x

subtract 20 from both sides and .15x from both

9=0.10x

divide by 0.10

:)