Math prob - simplify?

Question

(-3x^3y^2)(-2xy^-3) / -9x^2y^-5

Answer 1

In multiplication of exponents we add indices for same variables

(-3x^3y^2)(-2xy^-3)=(-3*-2)(x^3*x^1)(y^2...

                            =+6x^4y^-1

In division of exponents we subtract indices for the same variables

                (6x^4y^-1)/(-9x^2y^-5)

                     =(6/-9)*(x^4/x^2)(y^-1/y^-5)

                     =(2/3)x^6y^4.

the brackets on 2/3 means alot.

Answer 2

-2x^2y^4/3

Answer 3

(-3x^3y^2)(-2xy^-3)/-9x^2y^-5

= (-3)(-2)(x^3)(x)(y^2)(y^-3)/-9x^2y^-5

= [6][x^(3 + 1)][y^(2 - 3)]/-9x^2y^-5

= 6x^4y^-1/-9x^2y^-5

= (6/-9)(x^4/x^2)(y^-1/y^-5)

= [-2/3][x^(4 - 2)][y^(-1 + 5)]

= [-2/3][x^2][y^4]

= -2x^2y^4/3  

Answer 4

When you're multiplying the exponents add (and when you divide they subtract).

(+6x^4y^-1) / (-9x^2y-5)

4 - 2 = 2, and -1 - (-5) = 4, so

-2x^2y^4/3