Math probability help!?

Question

I hate probability....

Ok so knowing numbers 10 - 99 are two digit numbers...

and irrational numbers are not integers...

Q:

Suppose you choose a two digit number at random. What is the theoretical probability that its a square root is an integer?

Answer 1

there are 90 numbers in the sequence 10 to 99.  there are the following squares in that set:  16, 25, 36, 49, 64, 81.  there are 6 values in the set that have an integer sqrt root.  the probability of randomly selecting on of these values is 6 / 90 = 1 / 15

Answer 2

Okay, so there's 90 numbers you are able to pick. The numbers 4, 5, 6, 7, 8 and 9 all have squares in the double digits, meaning that 6 numbers out of those 90 have a square root that is an integer. This means 6/90 probability, or, simplified, 1/15.