Question:

Math problem?! (Sophomore Algebra)?

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Ok so i'm in 8th grade but i'm taking a sophomore math class! OMG!

Anyway,

−5(1 − 5x) +5(−8x− 2) = −4x− 8x

^^ Thats the problem. It's kinda easy but my brain's fried considering that today was the first day of school DX Thx for the homework mr.j. appreciated.

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  1. do all the multiplying first

    -5 + 25x - 40x -10 = -4x - 8x  

    combine like terms

    -15x - 15 = -12x

    get variables on one side constants on the other

    -15 = 3x

    solve for x

    x = -5

    I skipped some steps because if you are in 8th grade taking 10th grade math you probably know those steps.


  2. -5+25x-40x-10 = -12x

    -15x-15 = -12x

    -15 = 3x

    x = -5

  3. Whoa! You're in 8th Grade and doing sophomore algebra. I'm in 8th too, but I'm doing Algebra I.

  4. That is NOT sophmore algebra. I would know, I'm a sophmore.

    Anyway, that's really easy

    You just simplify it:

    -5 + 25x - 40x - 10 = -4x - 8x

    -15x - 15 = - 12 x

    3x = - 15

    x = - 5

  5. I GOT X= -5

    Im not 100% sure if it's right though. sorry..

    you distribute the outside number of each part of the equation.

    (-5+25x) + (-40x -10) = -12x

    when you do the math you get -15 + (-15x) = -12x

    subtract the -15x from -12x and you get 3x

    divide the -15 by 3 and you get x= -5


  6. x = -5

  7. Well, Algebra 1 is a Freshman class

    First you use distributive property so it would turn out to be...

    ((-5)+25x)-(40x-10) = -12x

    -15-15x =-12x

         +15x  +15x

    -15 = 3x

    /3       /3

    x= -5

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