Math problem....solve it to get best asnwer...?

Question

3 MEN GO INTO A MOTEL. THE MAN BEHIND THE DESK SAID THE ROOM IS $30, SO

EACH MAN PAID $10 AND WENT TO THE ROOM.

A WHILE LATER THE MAN BEHIND THE DESK REALIZED THE ROOM WAS ONLY $25, SO

HE SENT THE BELLBOY TO THE 3 GUYS' ROOM WITH $5.

ON THE WAY, THE BELLBOY COULDN'T FIGURE OUT HOW TO SPLIT $5 EVENLY

BETWEEN 3 MEN, SO HE GAVE EACH MAN A $1 AND KEPT THE OTHER $2 FOR

HIMSELF.

THIS MEANT THAT THE 3 MEN EACH PAID $9 FOR THE ROOM, WHICH IS A TOTAL OF

$27, ADD THE $2 THAT THE BELLBOY KEPT = $29.

WHERE IS THE OTHER DOLLAR?

Answer 1

in the end each man paid a total of $9 dollars for the room = $27. This includes the dollar they got back.

The bellboy kept $2. So then $27 - $2 = $25. The whole $30 thing dissappeared when the front desk paid a $5 refund. The number to get to is $25, not $30, the joke is flawed. Subtract not add. See?

answer

when 5$ was refunded it made the total paid by each man was 8.33 multiply that by3 equals 25 they gave the bell boy 2 and then gave each other 1 so each man actually paid 9.33$ not 9$

Answer 2

Amount to be accounted for:

= 3($10)

= $30

Accounted for as follows:

= desk man, ($30 - $5) + guests, ($1 * 3) + bellboy ($5 - 3)

= $25 + $3 + $2

= $30

Answer: $30 were distributed as follows: desk man, $25; guests, $3; bellboy, $2. That makes it $30—no dollar was lost.