Math problem?plzzzzzz help?

Question

how can you find the value of n in this equation.

200=n(4.00-1.80)-100

pls show solution

thanks

Answer 1

200 = n( 4.00-1.80 ) -100...First expand or multiply it out:

200 = 4n - 1.8n - 100........Then combine 4n and -1.8n:

200 = 2.2n - 100...............Then add 100 to both sides:

300 = 2.2n.......................Then divide both sides by 2.2:

136.36 = n

Answer 2

first distribute to get

200=4n-1.8n-100

combine like terms

200=2.2n-100

add 100 to both sides

300=2.2n

divide by 2.2 on both sides to get

136.3636(repeating)=n

Answer 3

200 = n(4.00 - 1.80) - 100

n(2.2) = 200 + 100

2.2n = 300

11n = 1,500

n = 1,500/11 or 136 4/11

Answer: n = 1,500/11 or 136 4/11

Proof:

200 = 1,500/11(4.00 - 1.80) - 100

200 = 1,500/11(2.2) - 100

200 = 3,300/11 - 100

200 = 300 - 100

200 = 200

Answer 4

200-100=n(4.00-1.80)

100=n(2.20)

100=n(22/10)

n=100*10/22

n=1000/22

n=45.45

Answer 5

200= 4n-1.80n-100

200=2.20n-100

300=2.20n

1.363636 and so on...= n

Answer 6

problem: 200= n(4-1.80)-100

use pemdas

200=2.20n-100

use the additive property of equality-- add 100 to both sides

200+100=2.20n-100+100

300=2.20n

divide both sides by 2.20-- use the property of equality to islolate the variable

n=136.363636

thats how i would do it, and im pretty sure thats right