Question:

Math question 6+4{3(9-4)}?

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Math question 6+4{3(9-4)}?

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  1. do the operation in the innermost parentheses first. so do 9-4 first:

    6+4[3(9-4)]

    6+4[3(5)]

    do the operation in the bracket next the 3(5):

    6+4(15)

    multiplication first then addition:

    6+60

    66


  2. 66

  3. chocolate milk

  4. search for and advanced algebra calculator(be sure to include the type of equation)  

  5. its 66 i did that in my head

  6. 6 + 4 { 3 (9-4 )}

    6 + 4 { 3 (5)}

    6 + 4 {15}

    6 + 60

    66


  7. First do what's inside of the parenthesis to get:

    6+4{3(5)} Now do what's inside the brackets to get:

    6+4{15} Now multiply first (order of operations) to get:

    6+60 now add and you get 66 <=== answer

  8. 66


  9. 66, first do the parenthesis inside the brackets, then multiply that by 3, then that times four plus 6...

  10. 6 + 4{3(9-4)} =

    6 + 4{3(5)} =

    6 + 4{15} =

    6 + 60 =

    66

  11. 1) solve (9-4)

    >>6+4[3(5)]

    2) distribute 3 into 5

    >>6+4(15)

    3) multiply/distribute 4 into 15

    >>6+60

    4) add

    >>66<<

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