Math question... Agebra Help please?

Question

Seperate the number 57 intotwo parts so that the first number is three less than twice the second number. Please explain what and what you did!!! help please

Answer 1

I just guessed a few numbers and came up with the correct answer.  the first number is 37 and the second number is 20

Answer 2

First, we need to build an equation. We know that the result has to be 57, so it will equal 57. After they say the first number 1s 3 less (-3) than twice the second number (which we have no information about)

So second number = x

first number = 2x-3 (2x represents twice the first number)

whole formula =

57 = x + 2x - 3

Now we have to resolve it that way:

57 + 3 = x + 2x - 3 +3

60 = x + 2x

60 = 3x

60/3 = 3x/3

20 = x

Now we have to find our numbers from the first formulas.

1st number = 2x-3

so we do

2*20 - 3 =

40 - 3 =

37

for the first one, it's just x, so it's going to be 20

now we verify:

37 + 20 = 57, that's right, so our first number is 37, and the second is 20.

Hope I helped!  

Answer 3

gosh!~ rather easy!~

let the first num x, the sec y

x+y=57

x+3=2y

work this formula system out.

x=37

y=20

that's it!~