Math question? Help please!! algebra i think?

Question

5x+2 over 3 = x-6 over 4

i don't get it!

yeah it's like 2 fractions...

it says solve and show work

thank you sooo much!!

Answer 1

You have to cross multiply.

1. So first multiply 5x+2 times 4

4(5x+2)

2. Then x-6 times 3.

3(x-6)

3. Set them equal to each other.

4(5x+2)=3(x-6)

4. Now distribute.

20x + 8 = 3x - 18

5. Now combine like terms by subtracting 3x from both sides, and subtracting 8 from both sides:

17X = -26

x= -26/17

Answer 2

Multiply all with 12

then we have

20x+8=3x-18

17x=-26

x=-26/17 -1  9/17

I hope it was helpful

good luck!

Answer 3

start by getting both fractions on one side of an equation that is equal to zero.   (5x+2)/3  -  (x-6)/4  = 0

Try it from here

Answer 4

(5x + 2)/3 = (x - 6)/4

=> 4(5x +2) = 3(x - 6)

=> 20x + 8 = 3x - 18

=> 20x - 3x = - 18 - 8

=> 17x = - 26

=> x = - 26/17<==ANSWER

Answer 5

First multiply both sides of the eqn. by 12 to eliminate the denominators:

Why 12?Because it is the LCM of both denominators (3 & 4):

12 [(5x + 2)/3] = [(x - 6)/4] 12

4 (5x + 2) = (x - 6) 3

20x + 8 = 3x -18

20x - 3x = -18 - 8

17x = -26

x = -26/17