Math question.. help please?

Question

ok.. so I'm really stuck on this problem.. there's a "aquarium" that is shaped like a rectangular prism. the width is 12 in. the height is 18 in. and the length is 24 in. the first question says what is the volume of the aquarium.. and i have that, which is 5,184 in cubic inches. But the next question is one gallon is equal to 213 cubic inches. How many gallons of water will the aquarium hold? i don't no that question.. and then the last one that i don't no is, If 10 gallons of water were poured into the empty aquarium, what would be the depth, in inches, of the water? show or explain how you got ur work. thanks for all the help i can get!

Answer 1

just take 5184/213 and you get 24.34 gallons in the aquarium,

For the last part multiply 213 by 10 to get 2130 gallons because it tells you 213=1 gallon so 10 gallons=2130

the length and width stay the same other wise you will change the shape of the aquarium, then you just figure out the depth 12width x 24length=288 and divide 2130/288= 7.4 inches depth

7.40 inches for the depth

Answer 2

To find the # of gallons just take 5184 and divide it by 213.

and to find the 10 gallons into cubic inches just take the 213 and multiply it by 10!!

Answer 3

You are correct that there is 5,184 cubic inches in the aquarium.  to determine the amount of gallons, divide 5,184 by 213 which equals 24.3 gallons.  

For the last question if there are ten gallons of water, then there are 2,130 cubic inches of water.  We know that the width (12) times the length (24) times the height (unknown here) must equal 2,130.  In other words 12 x 24 x H=2130

                  288H=2130

Therefore H = 2130/288 or H = 7.39.  So ten gallons of water would fill the tank 7.39 inches.