Math question. i forgot how to sovle it?

Question

Carol, Debbie, and Frieda practice the piano for a total of 23 hours per week. Carol practices twice as much as Frieda, and Debbie practices 3 hours more than Frieda every week. How many hours does Carol practice?

Answer 1

let frieda practices x hours in a week then

carol practices 2x hours in a week and

debbie practices x+3 hours in a week

we know that they practices 23 hours in a week

so

x + 2x + (x+3)=23

4x=20

x=5hours

frieda practices=5 hours

carol practices=2x=10 hours

debbie practices=x+3=8 hours

Answer 2

Let F be the amout of time that Frieda practices.

23 = 2F + F + (F+3)

Above, I got 2F because Carol's time of practice is twice as much as Frieda's. Since F is how much time Frieda practices, and Debbie practices 3 hours more than Frieda, you can add 3 to F. Hence, (F+3)

Then solve for F.

23 = 4F+3

subract 3 from each side

20 = 4F

divide each side by 4

5 = F

Frieda practices 4 hours per week.

Carol practices twice as much so, 4 times 2 is 8.

Carol practices 8 hours per week.

Answer 3

Hi,

2x + (x+3) + x = 23

Just solve for x and you are done.

good luck.

Answer 4

In this problem since Frieda practices smallest number of hours, therefore,

Let x be the number of hours that Freida practices.

Therefore: 2x is the number of hour that Carol practices.

and (x + 3) is for Debbie.

From the given question we have:

2x + (x + 3) + x =23, or

4x + 3 = 23,

4x + 3 - 3 = 23 - 3

4x = 20

x = 20/4 = 5 is for Frieda

for Carol:  2x = 2(5) = 10hours practiced.

and Debbie is (x + 3) = (5 + 3) = 8 hours practiced.

Since the question asked only for Carol, then the answer is 10 hours that Carol practiced.

Check:

  Carol + Debbie + Frieda

= 10hrs +  8 hrs   + 5hrs = 23hrs.