Math question will award 10 points for correct answer and work?

Question

Can some one please answer this question for me? Mary has $3.00 in nickels, diimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have? Please show work too. Thanks. I will award 10 points for the correct answer.

Answer 1

hi Kevin, here...

lets

the number of quarters coin = x, then the value = 25x cents.

the number of dimes coin = 2x, the value = 20x cents.

the number for nickels = 2x + 5 coins, the value = 10x + 25 cents.

total = 25x + 20x + 10x + 25 = 300 cents

55x = 300-25

55x = 275

x =5

then

the quarters = 5 coins

the dimes = 10 coins and

the nickels = 15 coins. done.

see ya..friend

Answer 2

Let n be the number of nickels, d be the number of dimes, and q be the number of quarters. You can make a system of three equations:

0.05n + 0.1d + 0.25q = 3 ($3.00 in nickels, dimes, and quarters)

d = 2q (twice as many dimes as quarters)

n = d + 5 (five more nickels than dimes)

Solve through substitution method. First substitute 2q for d in the third equation:

n = d + 5

n = 2q + 5

And now substitute 2q for d  and 2q + 5 for n in the first equation:

0.05n + 0.1d + 0.25q = 3

0.05(2q + 5) + 0.1(2q) + 0.25q = 3 (distributive property)

0.1q + 0.25 + 0.2q + 0.25q = 3 (combine like terms)

0.55q + 0.25 = 3 (subtract 0.25 from both sides)

0.55q = 2.75 (divide both sides by 0.55)

q = 5

And now you can solve for the other variables:

d = 2q

d = 2(5)

d = 10

n = d + 5

n = 10 + 5

n = 15

ANSWER: Mary has 15 nickels, 10 dimes, and 5 quarters.

Answer 3

here are the equations...

10d+5n+25q=300

d=2q

d=n-5

so 2q=n-5 and q=(n-5)/2

fill in d=2q to first eq

20q + 5n + 25q=300

45q+5n=300    ... now fill in q

45(n-5)/2 + 5n =300... mult by 2

45n-225 + 10n = 600

55n = 825

n = 15  therefore, d =10 and q = 5

Answer 4

5N+10D+25Q=300

D=2Q

N=2Q+5

substitute the D and N to the equation above

5(2Q+5)+10(2Q)+25Q=300

10Q+25+20Q+25Q=300

combine like terms

55Q=275

Q=5 (quarters)

D=2(Q)

D=2(5)

D=10 (dimes)

N=2(Q)+5

N=2(5)+5

N=10+5

N=15 (nickels)

check:

5 quarters = $1.25

+

10 dimes = $1.00

+

15 nickels = $0.75

equals $3.00

Answer 5

5 quarters,10 dimes,and 15 nickels.

1.25 in quarters

1.00 in dimes.

0.75 in nickels

=3.00

ta da!

Answer 6

No. of quarters (x):

$0.25x + $0.10(2x) + $0.05(2x + 5) = $3.00

$0.25x + $0.20x + $0.10x + $0.25 = $3.00

$0.55x = $2.75

x = 5

No. of dimes:

= 5 * 2

= 10

No. of nickels:

= 10 + 5

= 15

Answer: 15 nickels, 10 dimes and 5 quarters

Proof ($3.00 is the total value of coins):

= $0.05(15) + $0.10(10) + $0.25(5)

= $0.75 + $1.00 + $1.25

= $3.00

Answer 7

25(Q)x 5*=125 cents

10(d)x10=  100 cents  

**5x15=     75 cents

                +____

               300 cents or $3.00

*(3x2=6)    

**(10 dimes+5 nickels)