Math <span title="help!?!?!?!?!?!?!?!?!?!?!?">help!?!?!?!?!?!?!?!?!?!?!...</span>

Question

if i cant get this one, i cannot finish my homework! please help me or explain how to do it!

16u^2v^2-12u^3v-20v^3 / 4u^2v^2

Answer 1

= 16u^2v^2-12u^3v-20v^3 / 4u^2v^2

= (16u^2v^2 / 4u^2v^2) - (12u^3v / 4u^2v^2) - (20v^3/4u^2v^2)

= 4 - 12u/v - 20v/u^2

= (4 - 12u - 20v) / vu^2

Answer 2

I&#039;m assuming that everything before the slash is the numerator.  You should use parentheses to make it clearer. :)

(16u^2v^2-12u^3v-20v^3) / 4u^2v^2 =

Distribute the denominator.

(16u^2v^2 / 4u^2v^2) - (12u^3v / 4u^2v^2) - (20v^3 / 4u^2v^2) =

Factor.

[(4*4*u^2*v^2) / (4*u^2*v^2)] - [(4*3*u^2*u*v) / (4*u^2*v*v)] - [(4*5*v^2*v) / (4*u^2*v^2)] =

Simplify.

4 - [(3*u) / v] - [(5*v) / (u^2)] =

4 - (3u / v) - (5v / u^2) =

[4(u^2v / u^2v)] - [(3u / v)(u^2/ u^2)] - [(5v / u^2)(v / v)] =

(4u^2v / u^2v) - (3u^3 / u^2v) - (5v^2 / u^2v) =

(4u^2v - 3u^3 - 5v^2) / u^2v

Answer 3

16u^2v^2-12u^3v-20v^3 / 4u^2v^2 =

I factored a 4v out of the numerator and the denominator

4v (4u^2v - 3u^3 - 5v^2)

__________________

4v (u^2v)

The 4v cancels out of the numerator and denominator, leaving (4u^2v - 3u^3 - 5v^2) / (u^2v)

I don&#039;t think this polynomial can be factored any further ... good luck!

p.s. I just looked at the answer submitted by &quot;The Great One&quot;. I couldn&#039;t follow it, he (or she) might be on to something though. Breaking up the three terms in the numerator and placing them individually over the denominator is a smart first step.